BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Combination: No. of possible answers

Expert replies
by Naruto » Sun Jun 14, 2009 4:17 am
A teacher prepares a test. She gives 5 objective type questions out of which four have to be answered. Find out total no. of ways in which it can be answered if the first two questions have 3 answer choices and the last two questions have 4 choices.

A. 222
B. 816
C. 192
D. 100
E. 144



Well according to my calculation the answer was 832. Now thats not an option here. Please give the solution. Will post OA later.
Join the discussion
Source: — Problem Solving |

by tohellandback » Sun Jun 14, 2009 6:21 am
you sure you typed the question correct. Plz check ..I think information about 3rd question is required
The powers of two are bloody impolite!!
Join the discussion

by Naruto » Sun Jun 14, 2009 7:53 am
tohellandback wrote:you sure you typed the question correct. Plz check ..I think information about 3rd question is required
Right my mistake it says the last three questions instead of last two.
Join the discussion

by tohellandback » Sun Jun 14, 2009 8:27 am
IMO B,

IMO E. 144
two questions with 3 answer choices and 3 questions with 4 answer choices
we have two combinations available
1 three answer choice question and 3 four answer choice question

or,

2 three answer choice questions and 2 four answer choice question

for case1)

1 question can be selected in 2 ways from the three answer choice questions
so total number of ways to answer=2*3=6

3 four answer choice question can be selected in 1 way.
total number of ways these questions can be answered is 4*4*4=64
total number of ways the 4 questions can be answered=6*64=384

case 2:
2 question can be selected in 1 way from the three answer choice questions
these two questions can be answered in 3*3=9 ways
2 question can be selected in 3 way from the four answer choice questions
these questions can be answered in 4*4*3 ways=48
total number of ways this set of questions can be answered=9*48=432

total number of ways=432+384=816
The powers of two are bloody impolite!!
Join the discussion