BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

collection of tough problems from G PREP - 10

Expert replies
by abhasjha » Sat Feb 06, 2010 5:27 am
What is the greatest common divisor of positive integers m and n?

1) m is a prime number

2) 2n=7m
Join the discussion
Source: — Data Sufficiency |

by sanju09 » Sat Feb 06, 2010 5:54 am
abhasjha wrote:What is the greatest common divisor of positive integers m and n?

1) m is a prime number

2) 2n=7m
(1) If m is a prime number, then it may or may not be a prime factor of n. Hence the greatest common divisor may be either m or m n. Moreover, m and n are also not known. Insufficient

(2) If twice of one positive integer is 7 times another positive integer, then the former must have 7 as its factor, or n has 7 as one of its factor, for sure, whereas, m may or may not have 7 as one of its factor. Also, that the later must have 2 as its factor, or m has 2 as one of its factor, for sure, whereas, n may or may not have 2 as one of its factor. So, if n = 7 p and m = 2 q for some positive integers p and q, then their greatest common divisor is the greatest common divisor of the positive integers p and q that we don't know. Insufficient

Taken together

If m is prime, then q is 1, and the greatest common divisor of p and 1 is p. We don't know what's p. Still insufficient

[spoiler]E[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by ajith » Sat Feb 06, 2010 8:05 am
abhasjha wrote:What is the greatest common divisor of positive integers m and n?

1) m is a prime number

2) 2n=7m
1.) if m is a prime number the greatest common divisor of m and n can be either 1 or m
It is insufficient to conclude what is the gcd

2) 2n = 7m

N is a multiple of 7 and m is a multiple of 2 insufficient to calculate GCD

Now, If we combine these two

m=2 and n=7 and GCD is 1; Sufficient

C according to me
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by abhasjha » Mon Feb 08, 2010 12:20 am
Join the discussion

by papgust » Mon Feb 08, 2010 1:22 am
ajith wrote: 1.) if m is a prime number the greatest common divisor of m and n can be either 1 or m
It is insufficient to conclude what is the gcd

2) 2n = 7m

N is a multiple of 7 and m is a multiple of 2 insufficient to calculate GCD

Now, If we combine these two

m=2 and n=7 and GCD is 1; Sufficient
Ajith,

Can you explain statements I and II with a bit more in detail? Esp., the concept behind it.
Join the discussion

by sanju09 » Mon Feb 08, 2010 1:34 am
sanju09 wrote:
abhasjha wrote:What is the greatest common divisor of positive integers m and n?

1) m is a prime number

2) 2n=7m
(1) If m is a prime number, then it may or may not be a prime factor of n. Hence the greatest common divisor may be either m or m n. Moreover, m and n are also not known. Insufficient

(2) If twice of one positive integer is 7 times another positive integer, then the former must have 7 as its factor, or n has 7 as one of its factor, for sure, whereas, m may or may not have 7 as one of its factor. Also, that the later must have 2 as its factor, or m has 2 as one of its factor, for sure, whereas, n may or may not have 2 as one of its factor. So, if n = 7 p and m = 2 q for some positive integers p and q, then their greatest common divisor is the greatest common divisor of the positive integers p and q that we don't know. Insufficient

Taken together

If m is prime, then q is 1, and the greatest common divisor of p and 1 is p. We don't know what's p. Still insufficient

[spoiler]E[/spoiler]
Oh yes!!

If m is prime, then q is 1, to allow us take m = 2, now; and also if 2 n = 7 m, n = 7, and the greatest common divisor of m and n is 1.

[spoiler]sorry...it's C[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion