Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

coins tossed

Expert replies
by shibal » Sat Jun 27, 2009 7:08 am
what is the difference (approach) between these two exercises?

Five fair coins are tossed. What is the probability that exactly three of the coins land tails side up?

Five fair coins are tossed. What is the probability that at least three of the coins land tails side up?
Join the discussion
Source: — Problem Solving |

by Robinmrtha » Sat Jun 27, 2009 7:32 am
Five fair coins are tossed. What is the probability that exactly three of the coins land tails side up?

Solution

Exactly three of the coins land tails up = probability of 1st coin landing tails
and probability of 2nd coin landing tails and probability of 3rd coin landing tails
=1/2 x 1/2 x1/2
=1/8

Five fair coins are tossed. What is the probability that at least three of the coins land tails side up?

Solution
probability that at least three of the coins land tails side up =Probability of three coins landing tails up or Probability of 4 coins landing tails up or Probability of 5 coins landing tails up

=1/8 +1/16 +1/32
=7/32
Join the discussion

by shibal » Sat Jun 27, 2009 7:37 am
Robinmrtha wrote:Five fair coins are tossed. What is the probability that exactly three of the coins land tails side up?

Solution

Exactly three of the coins land tails up = probability of 1st coin landing tails
and probability of 2nd coin landing tails and probability of 3rd coin landing tails
=1/2 x 1/2 x1/2
=1/8
i've got 5/16....

possible outcomes 32 (2^5); different ways to have 3 tails 5!/3!(5-3)! = 10
10/32 --> 5/16...
Join the discussion

by DanaJ » Sat Jun 27, 2009 8:35 am
@shibal, you make a pretty good point. While the first answer is not entirely wrong, it only considers the situation where you have exactly the first three cases as your tails.

The way you've presented it makes sense, since it also takes into consideration the option that the three tails appear in other line-ups.

For your second question, the answer will indeed be probability of 3 + probability of 4 + probability of 5. You've already calculated the probability for 3 (5/16). The probability of 4 will be 5/32 or 1/8, since you have five available positions for that stray heads in there:

T T T T H
T T T H T
T T H T T
T H T T T
H T T T T

Getting all tails will obviously be 1/32. Add them all up to get 1/2. This also makes sense if you look at it this way: the probability you're looking for is 1 - (0, 1, 2 tails) which is 1 - (5, 4, 3 heads) or 1 - (the probability of getting at least three heads). Since the probability of getting heads or tails is the same, the probabilities for at least three heads or tails will be exactly the same.
Join the discussion