1/[v(2x)+vx]

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crackgmat007: Legendary Member; Posts: 882; Joined: Fri Feb 20, 2009 2:57 pmFollowed by: 1 member; Thanked: 15 times; GMAT Score:690

by crackgmat007 » Wed Jul 29, 2009 9:53 pm

If x > 0, then 1/[v(2x)+vx] =

A. 1/v(3x)
B. 1/[2v(2x)]
C. 1/(xv2)
D. (v2-1)/vx
E. (1+v2)/vx

I guess v = sqrt. Not sure.

OA - D

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Source: Beat The GMAT — Problem Solving | Wed Jul 29, 2009 9:53 pm

vyomb: Junior | Next Rank: 30 Posts; Posts: 23; Joined: Thu Feb 26, 2009 1:19 am; Thanked: 3 times; GMAT Score:650

ans

by vyomb » Thu Jul 30, 2009 2:50 am

my answer is D.

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truplayer256: Master | Next Rank: 500 Posts; Posts: 392; Joined: Thu Jan 15, 2009 12:52 pm; Location: New Jersey; Thanked: 76 times

by truplayer256 » Thu Jul 30, 2009 5:00 am

1/[sqrt(2x)+sqrt(x)]

1/[sqrt(2)*sqrt(x)+sqrt(x)]

1/[sqrt(x)(sqrt(2)+1)]

Multiply the numerator and denominator of the fraction by the conjugate of sqrt(2)+1.

1/[sqrt(x)(sqrt(2)+1)]*(sqrt(2)-1)/(sqrt(2)-1)

(sqrt(2)-1)/sqrt(x)*(2-1)=sqrt(2)-1/[sqrt(x)] D

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crackgmat007: Legendary Member; Posts: 882; Joined: Fri Feb 20, 2009 2:57 pmFollowed by: 1 member; Thanked: 15 times; GMAT Score:690

by crackgmat007 » Thu Jul 30, 2009 9:52 am

1/[sqrt(2)*sqrt(x)+sqrt(x)]

Missed the above. Tx.

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