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1/[v(2x)+vx]

Expert replies
Source: — Problem Solving |

ans

by vyomb » Thu Jul 30, 2009 2:50 am
my answer is D.
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by truplayer256 » Thu Jul 30, 2009 5:00 am
1/[sqrt(2x)+sqrt(x)]

1/[sqrt(2)*sqrt(x)+sqrt(x)]

1/[sqrt(x)(sqrt(2)+1)]

Multiply the numerator and denominator of the fraction by the conjugate of sqrt(2)+1.

1/[sqrt(x)(sqrt(2)+1)]*(sqrt(2)-1)/(sqrt(2)-1)

(sqrt(2)-1)/sqrt(x)*(2-1)=sqrt(2)-1/[sqrt(x)] D
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by crackgmat007 » Thu Jul 30, 2009 9:52 am
1/[sqrt(2)*sqrt(x)+sqrt(x)]
Missed the above. Tx.
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