DS number system

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nikhilagrawal: Senior | Next Rank: 100 Posts; Posts: 81; Joined: Thu Jun 12, 2008 1:57 pm; Thanked: 1 times

by nikhilagrawal » Sat Oct 04, 2008 2:11 pm

What is the value of y?

(1) 3|x2 – 4| = y – 2

(2) |3 – y| = 11

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Source: Beat The GMAT — Data Sufficiency | Sat Oct 04, 2008 2:11 pm

sethids: Master | Next Rank: 500 Posts; Posts: 135; Joined: Mon Jun 23, 2008 3:56 am; Thanked: 7 times

by sethids » Sat Oct 04, 2008 3:12 pm

Could you please confirm Stmt1 for this question?

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raju232007: Master | Next Rank: 500 Posts; Posts: 133; Joined: Sat Dec 29, 2007 2:43 am; Thanked: 12 times

by raju232007 » Sat Oct 04, 2008 11:03 pm

statement 1:

3|x^2-4|=y-2
The modulus of a umber is always greater than 0...so y-2>0
therefore y>2
but we cant determine the value of y from this statement

statement 2:

|3 – y| = 11
The two possible solutions for y are -8 and 14..
Statement 2 is insufficient..

From statement 1 and 2
we know that y>2 and y=14 & y=-8
so we know that y=14

Hence the ans is C

Let me know if you have any doubts..

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