BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Symbols and Operator

Expert replies
Source: — Data Sufficiency |

by bluementor » Mon May 11, 2009 2:36 am
∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
Join the discussion

by California4jx » Mon May 11, 2009 3:57 am
bluementor wrote:∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
the answer is B - but why cant we pick n to be 0 in second statement and that will make Addition, Multiplicaton to be true as well ?? --- that is where I fell down
Join the discussion

by sacx » Mon May 11, 2009 4:54 am
California4jx wrote:
bluementor wrote:∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
the answer is B - but why cant we pick n to be 0 in second statement and that will make Addition, Multiplicaton to be true as well ?? --- that is where I fell down
the second statement is 'n ∆ n = 0 for all integers n'. so the statement has to be true for all integers not just 0.
SACX
Join the discussion

by California4jx » Mon May 11, 2009 5:45 am
sacx wrote:
California4jx wrote:
bluementor wrote:∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
the answer is B - but why cant we pick n to be 0 in second statement and that will make Addition, Multiplicaton to be true as well ?? --- that is where I fell down
the second statement is 'n ∆ n = 0 for all integers n'. so the statement has to be true for all integers not just 0.
exactly, it has to be true for all integers including 0 !! -- why in the above explanaton are we missing 0 and just consider integers above 0 ... I understand the stmt B is true for SUB when we disregard 0 ---- but as u said its for all integers -- and if u consider 0 - then ADD, MUL supports STMT 2 --
Join the discussion

by sacx » Mon May 11, 2009 9:02 pm
California4jx wrote:
sacx wrote:
California4jx wrote:
bluementor wrote:∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
the answer is B - but why cant we pick n to be 0 in second statement and that will make Addition, Multiplicaton to be true as well ?? --- that is where I fell down
the second statement is 'n ∆ n = 0 for all integers n'. so the statement has to be true for all integers not just 0.
exactly, it has to be true for all integers including 0 !! -- why in the above explanaton are we missing 0 and just consider integers above 0 ... I understand the stmt B is true for SUB when we disregard 0 ---- but as u said its for all integers -- and if u consider 0 - then ADD, MUL supports STMT 2 --
Let me give you couple of examples

1. Subtraction
when n =0, n ∆ n = 0
when n = 1, n ∆ n = 0
when n = -3, n ∆ n = 0

For all integers, n ∆ n = 0

2. multiplication
when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 1
when n= -2, n ∆ n = 4

we can clearly see that n ∆ n is only true when n = 0

3. division

when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 1
when n= -2, n ∆ n = 1

true only when n = 0

4. addition

when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 2
when n= -2, n ∆ n = -4

again true only when n = 0.
SACX
Join the discussion

by California4jx » Tue May 12, 2009 4:46 am
sacx wrote:
California4jx wrote:
sacx wrote:
California4jx wrote:
bluementor wrote:∆ could be addition, subtraction, multiplication or division.

what is 1 ∆ 2?

Statement 1: n ∆ 0 = n

so ∆ could only be addition or subtraction.

if ∆ = addition, then 1 ∆ 2 = 3
if ∆ = subtraction, then 1 ∆ 2 = -1. Insufficient.

Statement 2: n ∆ n = 0 for all integers n.

so ∆ could only be subtraction. hence, 1 ∆ 2 = -1. Sufficient.

Choose B. What's the OA?

-BM-
the answer is B - but why cant we pick n to be 0 in second statement and that will make Addition, Multiplicaton to be true as well ?? --- that is where I fell down
the second statement is 'n ∆ n = 0 for all integers n'. so the statement has to be true for all integers not just 0.
exactly, it has to be true for all integers including 0 !! -- why in the above explanaton are we missing 0 and just consider integers above 0 ... I understand the stmt B is true for SUB when we disregard 0 ---- but as u said its for all integers -- and if u consider 0 - then ADD, MUL supports STMT 2 --
Let me give you couple of examples

1. Subtraction
when n =0, n ∆ n = 0
when n = 1, n ∆ n = 0
when n = -3, n ∆ n = 0

For all integers, n ∆ n = 0

2. multiplication
when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 1
when n= -2, n ∆ n = 4

we can clearly see that n ∆ n is only true when n = 0

3. division

when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 1
when n= -2, n ∆ n = 1

true only when n = 0

4. addition

when n = 0, n ∆ n = 0
when n= 1, n ∆ n = 2
when n= -2, n ∆ n = -4

again true only when n = 0.
Thanks !
Join the discussion