

As you can see from the image, the radius would have to be 4. Therefore, the maximum possible area would be 16pi
If the radius is 7, then the leftmost point on the circle will be (-3, 0), which violates the no negatives rule.aditi_bc wrote:I understand that the circle need to be in the first quadrant but fail to understand the logic behind radius=4 (& not 7). Could you pl explain further?
