If x, y, and z are nonzero numbers, is (x)(y + z) > 0?
(1) |x + y| = |x| + |y|
(2) |z + y| = |y| + |z|
(1) |x + y| = |x| + |y|
(2) |z + y| = |y| + |z|
If x, y, and z are nonzero numbers, is (x)(y + z) > 0?
Implies is x>0 if (y+z)>0 ? or Is x<0 if (y+z)<0 ?
(1) |x + y| = |x| + |y|
Implies x > 0 and y > 0 or x < 0 and y < 0 - Insufficient as it doesn't speak of z
(2) |z + y| = |y| + |z|
Implies z > 0 and y > 0 or z < 0 and y < 0 - Insufficient as it doesn't speak of x
From 1 and 2
Take condition x > 0 and y > 0, then the value of z > 0 [spoiler]and (x)(y + z) > 0[/spoiler]
Take condition x < 0 and y < 0, then the value of z < 0 [spoiler]and (x)(y + z) > 0[/spoiler]
Hence option C
