35 cans used in 6 days to feed 10 dogsmanelgirona wrote:At a pet center 35 cans of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
ajith wrote:food of dog for 1 day = 35/60manelgirona wrote:At a pet center 35 cans of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
7 dogs are left now
so total cans required = 35*7*12/60 = 49 Ans C
35 cans used in 6 days to feed 10 dogs
to feed 1 dog in a day ; we have to use 35/60 cans is used
to feed 7 dogs for 12 days; we have to use 35*7*12/60 = 49 cans
My problem approach will be like this:-Diet of dog per day = 35/60 cans[In this type of problems it is better to solve by unitary method like considering for per day per dog etc.]manelgirona wrote:At a pet center 35 dogscan of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
