absolute value Q36 page 39 premier 2013

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Source: — Data Sufficiency |

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by neelgandham » Thu Aug 23, 2012 6:54 am
5= |b+2| + |3-b|

If b < -2,
The value of b+2 is less than 0. So, |b+2|=-(b+2) because |X| = -X if x is a negative number.
The value of 3-b is greater than 0. So, |3-b| = 3-b because |X| = X if X is a non negative number.
|b+2| + |3-b| = -(b+2) + 3-b = -2b + 1(which is not always equal to 5. It is equal to 5 when b = -2)

If b > 3,
The value of b+2 is greater than 0. So, |b+2|=(b+2) because |X| = X if X is a non negative number.
The value of 3-b is less than 0. So, |3-b|=-(3-b) because |X| = -X if x is a negative number.
|b+2| + |3-b| = (b+2) + -(3-b) = 2b - 1(which is not always equal to 5. It is equal to 5 when b = 3)

If -2<b<3
The value of b+2 is greater than 0. So, |b+2|=(b+2) because |X| = X if X is a non negative number.
The value of 3-b is greater than 0. So, |3-b| = 3-b because |X| = X if X is a non negative number.
|b+2| + |3-b| = (b+2) + 3-b = 5

Hence -2<b<3 is an always-true condition. I would have provided you with the EXACT answer, if you have posted the complete question but that is OK.

Let me know if you need any further help!
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by kassim » Thu Aug 23, 2012 11:12 am
thank you for the explanation below is the exact question and in the question answers in the book they started with , a=5 when -2<= b<=3 before evaluate the statements, i want to know how they came up with these 2 numbers.

If a and b are integers and a= |b+2| + |3-b| , does a= 5 ?

1) b<3
2) b>-2

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by neelgandham » Thu Aug 23, 2012 11:31 am
b = -2 and b = 3 are the only points where the sign of the terms b+2 and 3-b reverses.

If b < -2 then b + 2 < 0
If b > -2 then b + 2 > 0

Similarly

If b > 3 then 3 - b < 0
If b < 3 then 3 - b > 0
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by GMATGuruNY » Thu Aug 23, 2012 4:39 pm
kassim wrote:thank you for the explanation below is the exact question and in the question answers in the book they started with , a=5 when -2<= b<=3 before evaluate the statements, i want to know how they came up with these 2 numbers.

If a and b are integers and a= |b+2| + |3-b| , does a= 5 ?

1) b<3
2) b>-2
Is |b+2| + |3-b| = 5?

|x-y| = the DISTANCE between x and y.
Thus:
|b+2| = |b-(-2)| = the distance between b and -2.
|3-b| = the distance between 3 and b.

Question rephrased:
Is the sum of the distance between b and -2 and the distance between b and 3 equal to 5?

Draw a number line:
...........-2.....................................3................

The distance between -2 and 3 is 5.
If b>3, then the distance between b and -2 will be greater than 5.
If b<-2, then the distance between b and 3 will be greater than 5.
Thus, if b>3 or b<-2, then the answer to the question stem is NO: the sum of the two distances will NOT be equal to 5.
For the sum of the two distances to be equal to 5, b must be BETWEEN -2 and 3, inclusive:

............-2<---|b+2|--->b<---|3-b|--->3................

As the number line shows, when b is between -2 and 3, inclusive, the sum of the two distances is equal to 5.

Question rephrased: Is b between -2 and 3, inclusive?

Statement 1: b<3
Statement 2: b>-2
When the two statements are combined, we know that b is between -2 and 3.
SUFFICIENT.

The correct answer is C.
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by kassim » Fri Aug 24, 2012 11:42 pm
Thank you That was very helpful