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by gmatboost » Wed Aug 10, 2011 7:59 am
Manhattan is correct here.

The error in the PFD solution as you have written it is that in each of the 6 options they provide, there are 2 possible ways for A and B to be inserted.

For example, in CDXX
It could be CDAB
It could be CDBA

So, for each of the 6 ways there are two options, 6*2 = 12.
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by trangle.nh » Wed Aug 10, 2011 8:03 am
Many thanks for your help.
I got it now!
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