If line k passes through the points (48, 33) and (31, 22), what is the x-intercept of line k?
A) -25 10/11
B) -3
C) -1 16/17
D) 1 16/17
E) 25 10/11
Answer: B
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Challenge: If line k passes through the points (48, 33) and
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Brent@GMATPrepNow
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Shahrukh@mbabreakspace
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Slope of the line= (33-22)/(48-31)= 11/17
Equation of the line= (y-22)/(x-31)= 11/17
=>11x-17y=-33
For x intercept, put y=0
So, x=-3
Equation of the line= (y-22)/(x-31)= 11/17
=>11x-17y=-33
For x intercept, put y=0
So, x=-3
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Brent@GMATPrepNow
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If we sketch the two given points, we can quickly see that the slope (aka rise/run) of the line = 11/17Brent@GMATPrepNow wrote:If line k passes through the points (48, 33) and (31, 22), what is the x-intercept of line k?
A) -25 10/11
B) -3
C) -1 16/17
D) 1 16/17
E) 25 10/11
So, we can use this information to plot another point on the line...
And another point...
..at which point, we can see that the x-intercept is -3
Answer: B
Cheers,
Brent
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GMATGuruNY
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Slope = ∆y/∆x = (33-22)/(48-31) = 11/17.Brent@GMATPrepNow wrote:If line k passes through the points (48, 33) and (31, 22), what is the x-intercept of line k?
A) -25 10/11
B) -3
C) -1 16/17
D) 1 16/17
E) 25 10/11
Since (x, 0) and (31, 22) must yield the same slope, we get:
(0-22)/(x-31) = 11/17
(x-31)(11) = (17)(-22)
x - 31 = (17)(-2)
x - 31 = -34
x = -3.
The correct answer is B.
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Jeff@TargetTestPrep
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We can let the x-intercept be a. Thus the coordinates of the x-intercept will be (a, 0). Since the x-intercept is on line k, the slope measured between the x-intercept and one of the two given points equals the slope measured between the two given points. Using the slope formula, we have:Brent@GMATPrepNow wrote:If line k passes through the points (48, 33) and (31, 22), what is the x-intercept of line k?
A) -25 10/11
B) -3
C) -1 16/17
D) 1 16/17
E) 25 10/11
(0 - 33)/(a - 48) = (22 - 33)/(31 - 48)
-33/(a - 48) = -11/(-17)
3/(a - 48) = 1/(-17)
a - 48 = -51
a = -3
Answer: B
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