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by MBA.Aspirant » Wed Jun 15, 2011 9:28 pm
A standard deck of 52 cards is shuffled and once card is drawn. What's the probability the the card is an ace or a face card?

It seems like an easy one but I don't know how many aces or faces exist in the deck..? Is it 4 aces and 12 faces?
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Source: — Problem Solving |

by Ian Stewart » Wed Jun 15, 2011 9:37 pm
MBA.Aspirant wrote:A standard deck of 52 cards is shuffled and once card is drawn. What's the probability the the card is an ace or a face card?

It seems like an easy one but I don't know how many aces or faces exist in the deck..? Is it 4 aces and 12 faces?
Yes, four Aces, four Kings, four Queens and four Jacks, so the answer would be 16/52 = 4/13. Fortunately you don't need to know anything at all about standard decks of cards for the GMAT.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

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by Geva@EconomistGMAT » Wed Jun 15, 2011 9:37 pm
MBA.Aspirant wrote:A standard deck of 52 cards is shuffled and once card is drawn. What's the probability the the card is an ace or a face card?

It seems like an easy one but I don't know how many aces or faces exist in the deck..? Is it 4 aces and 12 faces?
This feels like a concept a real GMAT question won't count on your general knowledge to include - it's not general knowledge like the number of days in a week, or the meaning of "leap year". So A real problem will specify the actual number.

There are four suits in a standard deck (clubs, hearts, diamonds and spades), and each suit contains 13 cards: number cards 2-10, face cards Jack, Queen, King, and an Ace. So 3 face cards times four suits makes 12 face cards, plus four aces makes for 16 wanted cards out of 52.
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