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by alltimeacheiver » Thu Feb 10, 2011 5:00 am
If 30!/10! is written as the product of consecutive integers, the largest of which is 30,
what is the smallest of the integers?
A. 1
B. 3
C. 7
D. 11
E. 20

Month Number of Days Worked
June 20
July 17
August 19
The table above shows the number of days worked by a certain sales representative in
each of three months last year. If the number of sales calls that the representative made
each month was proportional to the number of days worked in that month and if the
representative made a total of 168 sales calls in the three months shown, how many sales
calls did the representative make in August?
A. 50
B. 51
C. 56
D. 57
E. 60
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Source: — Problem Solving |

by Night reader » Thu Feb 10, 2011 5:09 am
alltimeacheiver wrote:If 30!/10! is written as the product of consecutive integers, the largest of which is 30,
what is the smallest of the integers?
A. 1
B. 3
C. 7
D. 11
E. 20
30!=30*29*28...*1
10!=10*9*8...*1
30!/10!=30*29*28...*11

IOM D

alltimeacheiver wrote:Month Number of Days Worked
June 20
July 17
August 19

The table above shows the number of days worked by a certain sales representative in each of three months last year. If the number of sales calls that the representative made each month was proportional to the number of days worked in that month and if the representative made a total of 168 sales calls in the three months shown, how many sales calls did the representative make in August?
A. 50
B. 51
C. 56
D. 57
E. 60
number of sales per day=X*(number of days), total sale calls=168 --> 168=X*(20+17+19), X=168/(20+17+19), X=3
total sales in Aug=3*19=57

IOM D
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by alltimeacheiver » Thu Feb 10, 2011 8:43 pm
thank you so much. I got stucked in the language part
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