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Can we solve this question with variables and equations?

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by [email protected] » Thu Dec 19, 2013 5:41 am
Question 2: Train A leaves the station and travels at 30 miles per hour. Three hours later, train Ð’ leaves the same station traveling in the same direction at 40 miles per hour on a parallel track. How far from the station was train A overtaken by train B?
(A) 90
(B) 180
(C) 200
(D) 300
(E) 360
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Source: — Problem Solving |

by theCodeToGMAT » Thu Dec 19, 2013 6:42 am
A = 30
B = 40

Time to Catch = GAP/(difference of speed) = 30*3/(10) = 9

Distance = 40*9 = 360

[spoiler]{E}[/spoiler]?
R A H U L
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by Brent@GMATPrepNow » Thu Dec 19, 2013 6:52 am
[email protected] wrote: Train A leaves the station and travels at 30 miles per hour. Three hours later, train Ð’ leaves the same station traveling in the same direction at 40 miles per hour on a parallel track. How far from the station was train A overtaken by train B?
(A) 90
(B) 180
(C) 200
(D) 300
(E) 360
Train A leaves the station and travels at 30 miles per hour...for 3 hours
Train A/s travel distance = (rate)(time) = (30)(3) = 90 miles
So, at the moment, there's a 90 mile gap between the trains

then . . .

train Ð’ leaves the same station traveling in the same direction at 40 miles per hour on a parallel track.
Train B's speed is 10 miles per hour FASTER than Train A's speed.
So, the gap between them SHRINKS at a rate of 10 miles per hour.

We want to know the time it takes for the gap to shrink from 90 miles to 0 miles (a difference of 90 miles).

Time = distance/rate = 90/10 = 9 hours

How far does train B travel in those 9 hours?
Distance = (rate)(time) = [spoiler](40)(9) = 360 miles = E [/spoiler]

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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