If -13 < 7a + 1 < 29 and 19 < 2 - b < 23, what is the maximum possible integer value of a + b?
A) -14
B) -13
c) -23
D) -12
E) -18
Answer is B) -13
can somebody please help with this problem
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- amandeep.hora
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-13 < 7a + 1 < 29 ---> -14 < 7a < 28 ---> -2 < a < 4amandeep.hora wrote:If -13 < 7a + 1 < 29 and 19 < 2 - b < 23, what is the maximum possible integer value of a + b?
19 < 2 - b < 23 ---> 17 < -b < 21 ---> -21 < b < -17
Hence, (a + b) < 4 + (-17) ---> (a + b) < -13
Maximum possible integral value of (a + b) is -14
Anju Agarwal
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- amandeep.hora
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thanks for taking the time to reply Anju !!
I still have a doubt though ,
I followed the below steps
-13 < 7a + 1 < 29 ---> -14 < 7a < 28 ---> -2 < a < 4
19 < 2 - b < 23 ---> 17 < -b < 21 ---> -21 < b < -17
then I chose -16 as the highest value that b can have and +3 highest integer value that a can have then their sum comes as -13 .
Still wondering what is wrong in my approach
really appreciate your help
Cheers,
Aman
I still have a doubt though ,
I followed the below steps
-13 < 7a + 1 < 29 ---> -14 < 7a < 28 ---> -2 < a < 4
19 < 2 - b < 23 ---> 17 < -b < 21 ---> -21 < b < -17
then I chose -16 as the highest value that b can have and +3 highest integer value that a can have then their sum comes as -13 .
Still wondering what is wrong in my approach
really appreciate your help
Cheers,
Aman
Regards
Aman
Aman
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- Brent@GMATPrepNow
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First, the question doesn't say that a and b are integers. It says that a+b is an integer.amandeep.hora wrote:thanks for taking the time to reply Anju !!
I still have a doubt though ,
I followed the below steps
-13 < 7a + 1 < 29 ---> -14 < 7a < 28 ---> -2 < a < 4
19 < 2 - b < 23 ---> 17 < -b < 21 ---> -21 < b < -17
then I chose -16 as the highest value that b can have and +3 highest integer value that a can have then their sum comes as -13 .
Still wondering what is wrong in my approach
really appreciate your help
Cheers,
Aman
Second, if -21 < b < -17, then b cannot equal -16
Cheers,
Brent