BTG problem 700+ discussion

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BTG problem 700+ discussion

by Night reader » Sun Jan 02, 2011 9:00 pm
If x and y are positive integers, and 1 is the greatest common divisor of x and y, what is the greatest common divisor of 2x and 3y?

A. can not be determined
B. 1
C. 2
D. 5
E. 6

[spoiler]this was extracted from the BTG problem set; the explanation suggests an error and trial method by plugging first 1 and 1 for x and y, then 3 and 2 for x and y. I have opted to use the prime factorization for x and y instead; given x and y have the greatest common factor (GCF) =1, any primes added to their products would still make GCF=1 unless we are not certain about the numbers x and y having both the factors 2 and 3. Hence for us it's difficult to determine from 2x and 3y which numbers have factors 2,3 and/or both => therefore it's answer A. Such problem could include many multipliers not only 2 and 3, and the problem's solution would need to be analytical rather one suggested 'trial and error'. What do you think?[/spoiler]
Source: — Problem Solving |

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by Tani » Sun Jan 02, 2011 9:25 pm
Your analysis is correct. To have any other common divisor, x would have to be a multiple of 3 and y a nultiple of 2. There are many combinations that would work and even more that wouldn't.

It may be much faster for most people to simply try two sets of values for x and y, one which gives another common factor and one that doesn't.
Tani Wolff