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Bowling Alley

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by DeepthiRajan » Thu Apr 29, 2010 6:27 am
Hi,

Would be great if someone can provide an explanantion for this:

At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $1.25 to bowl 1 game. If a person
has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day?

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11


Thanks in advance.
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by Fiver » Thu Apr 29, 2010 6:38 am
Total amount is 12.80 minus cost of shoes is 12.30.
Now if he were to play 10 games, it would cost him 12.5, which is greater than 12.3.
Hence I choose 9.
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by akhpad » Thu Apr 29, 2010 7:59 am
IMO: C
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by Scott@TargetTestPrep » Tue Oct 30, 2018 6:04 pm
DeepthiRajan wrote:Hi,

Would be great if someone can provide an explanantion for this:

At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $1.25 to bowl 1 game. If a person
has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day?

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
If we let n = the number of games the person can bowl, we can create the equation:

0.5 + 1.25n = 12.80

1.25n = 12.3

n = 9.84

So we see that 9 complete games can be played.

Answer: C

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