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by eaakbari » Sat Mar 27, 2010 3:55 am
Its a tricky question. Solution is attached
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by pradeepkaushal9518 » Sat Mar 27, 2010 4:22 am
1 only
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by eaakbari » Sat Mar 27, 2010 4:30 am
That is a wrong conclusion. Take simple numbers and cross check.
If we have the number 64 and divide it by 3, we get remainder as 1
Now 64 is the multiple of 8. If we divide 8 by 3 we get remainder as 2.
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by sanju09 » Sat Mar 27, 2010 5:09 am
eaakbari wrote:If a number when divided by 296 gives a remainder 75, find the remainder when the same number is divided by 37?




No answer as this is from a prep review book
If the new divisor is already a proper factor of the old divisor, then the old remainder can be taken as the new dividend; as in this case, 37 is already a proper factor of the old divisor 296, hence the old remainder 75, can be taken as the new dividend, and since 2 times 37 is 74, the new remainder is [spoiler]1[/spoiler].
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by srinivasarajui » Mon Mar 29, 2010 4:47 am
I agree with sanju09
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