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evenly divides..

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by debmalya_dutta » Wed Sep 08, 2010 4:55 am
7806 wrote:hi guys/experts.

i need a clarification about this statement:

if i say, interger a evenly divides i nterger b i.e b/a=k, so k=..??

(k=1,2,3,4....etc or k=0,2,4,6..etc. or can k also may be -ve.)

thanks.
"evenly divides" just means that the remainder = 0....
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by Stuart@KaplanGMAT » Wed Sep 08, 2010 9:11 am
debmalya_dutta wrote:
7806 wrote:hi guys/experts.

i need a clarification about this statement:

if i say, interger a evenly divides i nterger b i.e b/a=k, so k=..??

(k=1,2,3,4....etc or k=0,2,4,6..etc. or can k also may be -ve.)

thanks.
"evenly divides" just means that the remainder = 0....
This is correct. Another way you can express the idea is that if x evenly divides y, then x is a factor of y and y is a multiple of x; similarly, y/x is an integer. Sometimes we also say that "x goes into y".

"x evenly divides y" does NOT mean that y/x is even.
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by lokesh r » Wed Sep 08, 2010 12:01 pm
K can be defnitely be negative or positive.

K is positive when both a and b are positive or when both a and b are negative.

K is negative when either of a or b is negative.

Consider a =-10 and b=2

-10/2=-5 leaving remainder 0 and k=-5.
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by 7806 » Thu Sep 09, 2010 1:21 am
thanks guys , thanks stuart.
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by neerajkumar1_1 » Thu Sep 09, 2010 2:25 am
Just to add ... Do we also consider y=0 also as a soln to: x evenly divides y????
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