charge for the first one mile

This topic has expert replies
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

charge for the first one mile

by sanju09 » Sat Jul 31, 2010 4:30 am
If the cab charge for the first one mile is $1 and every subsequent 1/5th of a mile or fraction thereof is charged at 'a' cents, what is the total charge payable in cents for a distance of 'b' miles where 'b' is a whole number?
A. 1 + (b - 1) 5 a
B. 5 a b
C. 100 + (b - 1) 5 a
D. 100 + a b
E. 100 + (b - 1) a

[spoiler]Source: winningprep.com[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Source: — Problem Solving |

User avatar
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Wed Nov 11, 2009 6:39 am

by charan_nannuri » Sat Jul 31, 2010 4:45 am
charge for 1st mile = 1$=100 cents
after 1st mile charge for 1/5 th mile = a cents => charge for every mile after 1st mile =5a cents

charge for b miles = charge for 1st mile +charge for (b-1) miles
=100+(b-1)5a

so ANS :C

User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

by sanju09 » Sat Jul 31, 2010 4:50 am
charan_nannuri wrote:charge for 1st mile = 1$=100 cents
after 1st mile charge for 1/5 th mile = a cents => charge for every mile after 1st mile =5a cents

charge for b miles = charge for 1st mile +charge for (b-1) miles
=100+(b-1)5a

so ANS :C
excellent charan_nannuri! your most welcome!! please keep pouring in more for us

I can see you joined on 11 Nov 2009, and this is your first post on 31 Jul 2010, how come?
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

Senior | Next Rank: 100 Posts
Posts: 78
Joined: Thu Feb 21, 2008 9:05 am
Thanked: 7 times

by dinesh19aug » Sat Jul 31, 2010 1:56 pm
Sanju,
I see that solution is already posted. However whenever you come across such questions where answer involves ONLY VARIABLES, then you can plug in random values.

So lets us say that a = 1 cents(1 mile 5a = 5 cents), and b = 2 miles
Now find the charge: 100 + (2-1)* 5 = 105

Check the values in the options and only C satisfies it.


Thanks,
Dinesh