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average of m + 4 and n – 2

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by sanju09 » Wed Sep 15, 2010 9:20 pm
If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what is the average of m + 4 and n - 2?
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26

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by selango » Wed Sep 15, 2010 9:27 pm
m+n+19=45

m+4+n-2+17=45

m+4+n-2=28

(m+4+n-2)/2=28/2=14

Pick C
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by Scott@TargetTestPrep » Sat Jan 20, 2018 6:11 am
sanju09 wrote:If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what is the average of m + 4 and n - 2?
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26
We can use the formula for the arithmetic mean to create the equation:

(3 + 6 + 10 + m + n)/5 = 9

19 + m + n = 45

m + n = 26

We need to determine the average of m + 4 and n - 2; thus:

(m + 4 + n - 2)/2 = (m + n + 4 - 2)/2 = (26 + 4 - 2)/2 = 28/2 = 14

Answer: C

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