BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

average number of miles per gallon of gasoline for a car

Expert replies
by gmattesttaker2 » Tue Jul 03, 2012 11:50 pm
Hello,

The below is from the 10th edition of OG. Unfortunately, I don't have the answer with me.

What was the average number of miles per gallon of gasoline for a car during a certain trip?

1) The total cost of the gasoline used by the car for the 180 mile trip was $12.00
2) The cost of the gasoline used by the car for the trip was $1.20 per gallon

I am thinking that the answer is [spoiler](E)[/spoiler]

Using 1) I am getting $15/- of gasoline per mile. However, this is not what we want. 2) is insufficient as well.

Any thoughts on this? Thanks a lot.

Best Regards,
Sri
Join the discussion
Source: — Data Sufficiency |

by niketdoshi123 » Wed Jul 04, 2012 4:44 am
gmattesttaker2 wrote:
What was the average number of miles per gallon of gasoline for a car during a certain trip?

1) The total cost of the gasoline used by the car for the 180 mile trip was $12.00
2) The cost of the gasoline used by the car for the trip was $1.20 per gallon
Let the avg number of miles traveled during a certain trip = D
and the number of gallons of gasoline used during that trip = G

according to the question , we need to find "D/G"

Statement 1 INSUFFICIENT

It provides the value of D and the cost of G.

statement 2 INSUFFICIENT

It provides the cost of per gallon of gasoline. no information about G or D

Statement 1 & 2 combined

we can calculate G using both the statements
=>G = $12/$1.2 = 10
and we have the value of D from the 1st statement

Hence we can now find the value of D/G = 180/10 = 18
So SUFFICIENT
Hence the answer is C
Join the discussion

by gmattesttaker2 » Wed Jul 04, 2012 10:15 am
niketdoshi123 wrote:
gmattesttaker2 wrote:
What was the average number of miles per gallon of gasoline for a car during a certain trip?

1) The total cost of the gasoline used by the car for the 180 mile trip was $12.00
2) The cost of the gasoline used by the car for the trip was $1.20 per gallon
Let the avg number of miles traveled during a certain trip = D
and the number of gallons of gasoline used during that trip = G

according to the question , we need to find "D/G"

Statement 1 INSUFFICIENT

It provides the value of D and the cost of G.

statement 2 INSUFFICIENT

It provides the cost of per gallon of gasoline. no information about G or D

Statement 1 & 2 combined

we can calculate G using both the statements
=>G = $12/$1.2 = 10
and we have the value of D from the 1st statement

Hence we can now find the value of D/G = 180/10 = 18
So SUFFICIENT
Hence the answer is C
Hello Niket,

Thanks for the explanation. Sorry, I am not that good at these average problems. Is this correct:

Avg. number of miles per gallon of gasoline = Total Miles/Total Gallons

Let, total miles = D
and total gallons = G

So, Avg. number of miles per gallon of gasoline = D/G


Statement 1
180 miles - $12.00
1 mile - x

So, x = $1/15

$1/15 for 1 mile. No info about Total Gallons. Insufficient

Statement 2

$1.20 per Gallon

No info about Total Miles and Total Gallons. Insufficient


However, I am not clear after this point how we are getting the total gallons value. Can you please help? Thanks a lot.


Best Regards,
Sri
Join the discussion

by niketdoshi123 » Wed Jul 04, 2012 8:47 pm
gmattesttaker2 wrote:
However, I am not clear after this point how we are getting the total gallons value. Can you please help? Thanks a lot.
hi Sri,

after combining the two statements, we know the total cost of gasoline used and cost of per gallon of gasoline.

So, # of gallons of gasoline = Total cost of gasoline/Cost of per gallon of gasoline

=> G = $12/$1.2 = 10
Join the discussion

by gmattesttaker2 » Thu Jul 05, 2012 9:24 pm
niketdoshi123 wrote:
gmattesttaker2 wrote:
However, I am not clear after this point how we are getting the total gallons value. Can you please help? Thanks a lot.
hi Sri,

after combining the two statements, we know the total cost of gasoline used and cost of per gallon of gasoline.

So, # of gallons of gasoline = Total cost of gasoline/Cost of per gallon of gasoline

=> G = $12/$1.2 = 10

Hi Niket,

It is clear now. Thank you very much for your explanation and help.

Best Regards,
Sri
Join the discussion