hey_thr67 wrote:In a group of 11 people, x is 32 years old and y is 4 years younger than x. If x and y are replaced by two other people, the average age of the group drops by 1 year. Find the average age of the two people replacing x and y.
1) 26
2) 28
3) 29
4) 30
5) 24.5
Hi, there. I'm happy to help with this.
First of all, here's a blog I wrote about a general approach to "average questions" like the one you posted here:
https://magoosh.com/gmat/2012/gmat-avera ... -formulas/
Here's a solution to your question.
X is 32 years old
Y is 28 years old
so X + Y = 60.
Let's say the average of the 11 people is M. We know M = (sum of all 11 ages)/11, or
sum1 = 11M
(I'm calling this "sum1" because it's before we replace X & Y)
Now, replace X & Y with two younger people --- call them P & Q --- and the average drops by one:
sum2 = 11(M - 1) = 11M - 11 = sum1 - 11
sum1 - sum2 = 11
(X + Y + nine others) - (P + Q + same nine other) = 11
(X + Y) - (P + Q) = 11
60 - (P + Q) = 11
(P + Q) = 49
(P + Q)/2 = 49/2 = 24.5
Thus, the average ages of the two new people is 24.5, answer
E.
Does all this make sense?
Here's a free practice question about averages,
https://gmat.magoosh.com/questions/349
When you submit your answer, the following page will have the complete video explanation.
Let me know if you have any further questions.
Mike
