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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## At the neginning of a certain job, the counter of a... tagged by: BTGmoderatorLU ##### This topic has 2 expert replies and 0 member replies ### Top Member ## At the neginning of a certain job, the counter of a... At the beginning of a certain job, the counter of a photocopy machine read 1254. At the end of the job, the counter read 2334. If the running time for the job was 30 minutes, then what was the average operating speed of the machine in copies per second? A) .6 B) 1.1 C) 6 D) 36 E) 2160 The OA is A. Experts, any suggestion? The total of copies during the 30 minutes will be, 2334 - 1254 = 1080. Now I just need to convert the 30 minutes to seconds and it will be 1800 seconds. Finally, the rate of the machine in those 30 minutes will be, 1080 / 1800 = 0.6 copies per second, right? Thanks in advance. ### GMAT/MBA Expert Legendary Member Joined 14 Jan 2015 Posted: 2667 messages Followed by: 122 members Upvotes: 1153 GMAT Score: 770 LUANDATO wrote: At the beginning of a certain job, the counter of a photocopy machine read 1254. At the end of the job, the counter read 2334. If the running time for the job was 30 minutes, then what was the average operating speed of the machine in copies per second? A) .6 B) 1.1 C) 6 D) 36 E) 2160 The OA is A. Experts, any suggestion? The total of copies during the 30 minutes will be, 2334 - 1254 = 1080. Now I just need to convert the 30 minutes to seconds and it will be 1800 seconds. Finally, the rate of the machine in those 30 minutes will be, 1080 / 1800 = 0.6 copies per second, right? Thanks in advance. Sure. Just note that once you have 1080/1800, you know the answer is less than 1. Only A will work. No need to do any more arithmetic than necessary. _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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LUANDATO wrote:
At the beginning of a certain job, the counter of a photocopy machine read 1254. At the end of the job, the counter read 2334. If the running time for the job was 30 minutes, then what was the average operating speed of the machine in copies per second?

A) .6
B) 1.1
C) 6
D) 36
E) 2160
Since 30 minutes is 30 x 60 = 1800 seconds, the rate in seconds is:

(2334 - 1254)/1800 = 1,080/1800 = 108/180 = 12/20 = 3/5 = 0.6

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