At Megalomania Industries, factory workers were paid $20 per

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Source: Princeton Review

At Megalomania Industries, factory workers were paid $20 per hour in 1990 and $10 per hour in 2000. The CEO of Megalomania Industries was paid $5 million per year in 1990 and $50 million per year in 2000. The percent increase in the pay of Megalomania's CEO from 1990 to 2000 was what percent greater than the percent the decrease in the hourly pay of Megalomania's factory workers over the same period?

A. 850%
B. 900%
C. 950%
D. 1,700%
E. 1,900%

The OA is D

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by swerve » Wed Jun 26, 2019 12:44 pm
Percent decrease in worker's pay \(=\frac{20-10}{20}\cdot 100\% = 50\%\)

Percent increase in CEO's pay \(= \frac{50-5}{5} \cdot 100 \%=900\%\)

The question is asking: 900 is what percent greater than 50?

If \(50\) is \(100\%\), then \(900\) is \(1800\%\). So, \(900\) is \(1700\%\) greater than \(50\).

Therefore, __D__

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by Scott@TargetTestPrep » Mon Jul 01, 2019 4:08 pm
BTGmoderatorLU wrote:Source: Princeton Review

At Megalomania Industries, factory workers were paid $20 per hour in 1990 and $10 per hour in 2000. The CEO of Megalomania Industries was paid $5 million per year in 1990 and $50 million per year in 2000. The percent increase in the pay of Megalomania's CEO from 1990 to 2000 was what percent greater than the percent the decrease in the hourly pay of Megalomania's factory workers over the same period?

A. 850%
B. 900%
C. 950%
D. 1,700%
E. 1,900%

The OA is D
First, let's calculate the percent decrease for the workers, using the formula (New - Old)/Old x 100:

(10 - 20)/20 x 100 = -1/2 x 100 = -50 → 50% decrease

Next we calculate the percent increase for the CEO:

(50,000,000 - 5,000,000)/5,000,000 x 100

45,000,000/5,000,000 x 100

9 x 100 = 900 → 900% increase

Thus:

(900 - 50)/50 x 100

850/50 x 100 = 1700%

Answer: D

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