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At a community center, three separate pumps- A, B, and C- st

Expert replies
by alanforde800Maximus » Wed Oct 19, 2016 9:48 pm
At a community center, three separate pumps- A, B, and C- started to fill an empty swimming pool at 8:00 AM, and each pump worked at its own constant rate until the pool was full. Was the pool completely filled at 3:00 PM?


1) Working alone, pump C could fill 3/10 of the pool in 126 minutes.
2) Working together, pumps A and B could fill 1/8 of the pool in 55 minutes.

Please assist with above problem.
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Source: — Data Sufficiency |

by GMATGuruNY » Thu Oct 20, 2016 2:58 am
alanforde800Maximus wrote:At a community center, three separate pumps- A, B, and C- started to fill an empty swimming pool at 8:00 AM, and each pump worked at its own constant rate until the pool was full. Was the pool completely filled at 3:00 PM?


1) Working alone, pump C could fill 3/10 of the pool in 126 minutes.
2) Working together, pumps A and B could fill 1/8 of the pool in 55 minutes.

Please assist with above problem.
8am - 3pm = 7 hours = 420 minutes.

Statement 1:
Let the pool = 10 liters, implying that 3/10 of the pool = (3/10)(10) = 3 liters.
Since C can pump 3 liters in 126 minutes, C's rate = w/t = 3/126 = 1/42 liters per minute.
Amount pumped by C in the 420 minutes between 8am and 3pm = rt = (1/42)(420) = 10 liters.
Thus, the 10-liter pool will be filled by 3pm.
SUFFICIENT.

Statement 2:
Let the pool = 8 liters, implying that 1/8 of the pool = (1/8)(8) = 1 liter.
Since A and B together can pump 1 liter in 55 minutes, the combined rate for A and B = w/t = 1/55 liters per minute.
Amount pumped by A and B in the 420 minutes between 8am and 3pm = rt = (1/55)(420) = 84/11 = less than 8 liters.
Thus, A and B alone cannot fill the 8-liter pool by 3pm.
Since C's rate is unknown, it is not possible to determine whether the pool will be filled by 3pm.
INSUFFICIENT.

The correct answer is A.
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by fiza gupta » Sat Oct 22, 2016 11:05 am
given) all started to fill the pool at 8:00AM

1) c fill 3/10 in 126 minutes
full pool in (126*10/3)/60 hours 7 hours
if C started alone at 8 he will finish at 3,
b and A working together with c will increase the speed and work will be finished earlier
SUFFICIENT

2) a and b 1/8 in 55 minutes
full pool : (55*8)/60 = 7.3 hours> 7 hours
c speed unknown, so it will depend upon C's speed whether the work will be finished till 3
INSUFFICIENT

SO A
Fiza Gupta
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by Jay@ManhattanReview » Fri Dec 30, 2016 4:28 am
alanforde800Maximus wrote:At a community center, three separate pumps- A, B, and C- started to fill an empty swimming pool at 8:00 AM, and each pump worked at its own constant rate until the pool was full. Was the pool completely filled at 3:00 PM?


1) Working alone, pump C could fill 3/10 of the pool in 126 minutes.
2) Working together, pumps A and B could fill 1/8 of the pool in 55 minutes.

Please assist with above problem.
Total time during 8am to 3pm = 7 hours

S1: Given that pump C could fill 3/10 of the pool in 126 minutes, means that pump C can fill the pool in (126*10)/3 minutes = 7 hours. This means that had only pump C been into the operation, it could have filled the pool. However, we know that pump A and pump B are also in operation, thus the pool must have been filled before 3 pm. But we can surely say that the pool was full at 3 pm. Sufficient.

S2: Given that working together, pumps A and B could fill 1/8 of the pool in 55 minutes, means that pump A and B can fill the pool in 55*18 minutes = 7 hours 20 minutes. Thus A and B together can fill the poll by 3.20 pm. Of cource, we know that pump C was also in operation, and it must have contributed something; however its rate is not known. If pump C's rate is high, the pool would be full well before 3 pm (the answer is YES); however if its rate is too low, the pool would be filled betweem 3 pm to 3.20 pm (the answer is NO). Insufficient.

Hope this helps!

-Jay
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