the probability of getting two "heads" on three tosses should be 3/8.
arrangements will be HHT,HTH,THH ..so each arrangement has probability of 1/8 and hecne total probabilty of 3/8.
As part of a game, four people each must secretly choose an
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abhishekg21
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gmatter2012
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was just trying to brush up my probability when I came across this thread .
Would like to continue from here .
The probability of 2 heads on 3 tosses is 3/8
HHT this is one probability but the heads could occur in the 2 and 3 throws as well so THH and HTH are also possible.
so total no. of ways heads can be arranged is 3!/2! using permutation formula .hence 3/8
P.S. - I do have a question which I shall post after I hear from you.
Would like to continue from here .
The probability of 2 heads on 3 tosses is 3/8
HHT this is one probability but the heads could occur in the 2 and 3 throws as well so THH and HTH are also possible.
so total no. of ways heads can be arranged is 3!/2! using permutation formula .hence 3/8
P.S. - I do have a question which I shall post after I hear from you.
