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As part of a game, four people each must secretly choose an

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by abhishekg21 » Fri Oct 22, 2010 2:22 am
the probability of getting two "heads" on three tosses should be 3/8.

arrangements will be HHT,HTH,THH ..so each arrangement has probability of 1/8 and hecne total probabilty of 3/8.
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by gmatter2012 » Sun Jun 03, 2012 12:33 am
was just trying to brush up my probability when I came across this thread .

Would like to continue from here .

The probability of 2 heads on 3 tosses is 3/8

HHT this is one probability but the heads could occur in the 2 and 3 throws as well so THH and HTH are also possible.

so total no. of ways heads can be arranged is 3!/2! using permutation formula .hence 3/8

P.S. - I do have a question which I shall post after I hear from you.
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