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Some additional brackets would help understand the original question. Plus I think you added an extra 2.parulmahajan89 wrote:if XY=1 then what is the value of 2^(X+Y)²/ 2^(X-Y)²
1)2
2) 4
3) 8
4) 16
5) 32
NOT sure what I did wrong here I think answer is 8. But correct answer is 16?
Let x=y=1.parulmahajan89 wrote:if XY=1 then what is the value of 2^(X+Y)^2/ 2^(X-Y)2^2
1)2
2) 4
3) 8
4) 16
5) 32
If xy = 1, then (x + y)^2 = x^2 + y^2 + 2, and (x – y)^2 = x^2 + y^2 – 2. Using Rules of Exponents, we can haveparulmahajan89 wrote:if XY=1 then what is the value of 2^(X+Y)^2/ 2^(X-Y)2^2
1)2
2) 4
3) 8
4) 16
5) 32
NOT sure what I did wrong here I think answer is 8. But correct answer is 16?
A nice and sweet solution in its simplicity. Thanks.GMATGuruNY wrote:Let x=y=1.parulmahajan89 wrote:if XY=1 then what is the value of 2^(X+Y)^2/ 2^(X-Y)2^2
1)2
2) 4
3) 8
4) 16
5) 32
Then:
2^(x+y)² / 2^(x-y)² = 2^(1+1)² / 2^(1-1)² = 2�/2� = 16/1 = 16.
The correct answer is D.
