confuse mind wrote:What is the number of ways in which 5 books can be arranged 3 at a time?
The solution will be 5P3 * 2! or 5P3
The language of above question always confused me in the sense that the left over 2 books are also to b arranged or not?
What is the number of ways in which 6 books can be arranged 3 at a time?
6P3 * 3! or 6P3
For your question, it looks like we don't need to worry about the remaining books (so the answers are 5P3 and 6P3).
By the way, we can answer this question without permutation notation.
We can take the task of arranging 3 books (from 5 books), and break it into stages.
Stage 1: Select a book for the first position.
This can be accomplished in 5 ways
Stage 2: Select a book for the middle position.
Since we already selected a book for stage 1, there are 4 books remaining, so this stage can be accomplished in 4 ways.
Stage 3: Select a book for the last position.
This stage can be accomplished in 3 ways.
At this point, we can apply the Fundamental Counting Principle (FCP), to see that all 3 stages can be completed in 5x4x3 ways (60 ways)
Cheers,
Brent
PS: For more information about the FCP, we have this free video:
https://www.gmatprepnow.com/module/gmat-counting?id=775Brent Hanneson - Creator of GMATPrepNow.com
