coolhabhi wrote:The sum of first four terms of an Arithematic Progression is 28 and sum of the first eight terms of the same series is 88. Find the sum of the first 16 terms of the series
A)346
B)340
C)304
D)268
OA : C
Sum of the first 4 terms = 28.
Sum of the next 4 terms = sum of the first 8 terms - sum of the first 4 terms = 88-28 = 60.
Difference between the sums = 60-28 = 32.
Implication:
Each set of 4 terms yields a sum that is 32 greater than the sum of the PRECEDING 4 terms.
Thus:
Sum of the next 4 terms = 60+32 = 92.
Sum of the last 4 terms = 92+32 = 124.
Final tally:
28 + 60 + 92 + 124.
Since the sum of the units digits = 8+0+2+4 = 14, the correct answer choice must have a units digit of 4.
The correct answer is
C.
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