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[email protected]: Senior | Next Rank: 100 Posts; Posts: 30; Joined: Sun Jun 27, 2010 7:55 pm

by [email protected] » Tue Jun 29, 2010 7:29 pm

Four horses are tethered at the four corners of a square of side 14cm such that two horses along the same side can
just reach each other. They were able to graze the area in 11 days. How many days will they take in order to graze the left out area?

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Source: Beat The GMAT — Problem Solving | Tue Jun 29, 2010 7:29 pm

ilikaroy: Junior | Next Rank: 30 Posts; Posts: 12; Joined: Thu May 13, 2010 10:08 pm; Thanked: 1 times

by ilikaroy » Tue Jun 29, 2010 7:55 pm

I think you need to mention that the length of rope is same for all the horses. Otherwise the answer will be different.

Am I correct?

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amising6: Master | Next Rank: 500 Posts; Posts: 294; Joined: Wed May 05, 2010 4:01 am; Location: india; Thanked: 57 times

by amising6 » Tue Jun 29, 2010 8:07 pm

[email protected] wrote:Four horses are tethered at the four corners of a square of side 14cm such that two horses along the same side can
just reach each other. They were able to graze the area in 11 days. How many days will they take in order to graze the left out area?

so assuming they will cover 7 cm of side by both horse so basically it will be covering area with radius of 7 cm i.e are=(1/4)(22/7)*7*7 =77/2 cm^2 each by each horse so 2 horse on which are teethered on one side and can meet will cover 77/2*2=77cm^2 area so talltogether four horse will cover 77*2=154 cm^2 in 11 days
so in 1 day=154/11=14
area remaining to be grazed 14*14 -154=32
days 32/24=4/3 days

Ideation without execution is delusion

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[email protected]: Senior | Next Rank: 100 Posts; Posts: 30; Joined: Sun Jun 27, 2010 7:55 pm

by [email protected] » Tue Jun 29, 2010 9:13 pm

Ans. 3

dont know how they get it.

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Rahul@gurome: GMAT Instructor; Posts: 1179; Joined: Sun Apr 11, 2010 9:07 pmFollowed by: 88 members; Location: Milpitas, CA; Thanked: 447 times

by Rahul@gurome » Tue Jun 29, 2010 9:49 pm

Each horse grazes pi*1/4*(7^2) area.
So 4 horses graze pi*(7^2) = 154 area.
What we have is that 154 area is being grazed in 11 days.
Remaining area to be grazed is 14*14 - 154 = 196 - 154 = 42.
So this will take (11/154)* 42 = 3 days.

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