Data Sufficiency

prachich1987 wrote:@ Anurag & anshumishra,

I have attached herewith the figure which satisfies the statement 2 & the overlapping portion is not a perfect square.
There is some problem with my paints & hence I draw it in ppt.
It may not be accurate but I think it will solve the purpose.

Anurag@Gurome wrote:Sorry.
I misunderstood your last post.

You're correct.
Without statement 1 we cannot conclude the overlapping part is a square.

anshumishra wrote:

prachich1987 wrote:@ Anurag & anshumishra,

I have attached herewith the figure which satisfies the statement 2 & the overlapping portion is not a perfect square.
There is some problem with my paints & hence I draw it in ppt.
It may not be accurate but I think it will solve the purpose.

Thanks prachich1987 !
That is the point I have made in my previous post. So, Please confirm that the OA is C.

prachich1987 wrote:

anshumishra wrote:

prachich1987 wrote:@ Anurag & anshumishra,

I have attached herewith the figure which satisfies the statement 2 & the overlapping portion is not a perfect square.
There is some problem with my paints & hence I draw it in ppt.
It may not be accurate but I think it will solve the purpose.

Thanks prachich1987 !
That is the point I have made in my previous post. So, Please confirm that the OA is C.

No anshumishra
The OA given by Kaplan is B.
That's why I got confused & posted this question.
FYI, I have attached herewith the OE

jaxis wrote:Guys let me try to explain my doubt clearly. I think Anshu misunderstood it.

Either statement alone is not sufficient.I think people agree on this.

My point is Both statements combined are not sufficient to solve the problem.

Lets take two cases.

Case1: Side of Square 1 (S1) = side of square 2 (s2).

In this case if we combine both the statements , the overlapping area is a square for sure.Hence we can say that both statements are sufficient.hence C.and the area is '4'.

But we are over looking a few cases.
For example, case 2.

Case 2: Side of square 1 (S1) = half ( side of square 2 (s2)).

S1 = S2/2



l]

As per me this figure follows both the conditions and still gives us a overlapping area which is not square.
So, I think we cant uniquely find an are of theoverlapping region using the bioth statements.

Hence, E.

anshumishra wrote:

jaxis wrote:Guys let me try to explain my doubt clearly. I think Anshu misunderstood it.

Either statement alone is not sufficient.I think people agree on this.

My point is Both statements combined are not sufficient to solve the problem.

Lets take two cases.

Case1: Side of Square 1 (S1) = side of square 2 (s2).

In this case if we combine both the statements , the overlapping area is a square for sure.Hence we can say that both statements are sufficient.hence C.and the area is '4'.

But we are over looking a few cases.
For example, case 2.

Case 2: Side of square 1 (S1) = half ( side of square 2 (s2)).

S1 = S2/2



l]

As per me this figure follows both the conditions and still gives us a overlapping area which is not square.
So, I think we cant uniquely find an are of theoverlapping region using the bioth statements.

Hence, E.

@jaxis
The question is not to prove that the overlapping area is square or not. It is just to find whether we can determine the area or not. "B" is sufficient. Please check the OA posted above or my first solution (which i have edited since).

Also, In the diagram you have attached , it doesn't seem "C" is in center of the square. I am not sure if that was intentional or not, however based on the facts given in "B" it must be at the center.
As, CE = CF = 2sqrt2
And EF = 4, The triangle ECF is a right angled triangle.

I might have missed something, since i just read few lines of your question, however feel that would change your thought a bit. Let me know if you want us to look at a particular part of it.

anshumishra wrote:

jaxis wrote:Guys let me try to explain my doubt clearly. I think Anshu misunderstood it.

Either statement alone is not sufficient.I think people agree on this.

My point is Both statements combined are not sufficient to solve the problem.

Lets take two cases.

Case1: Side of Square 1 (S1) = side of square 2 (s2).

In this case if we combine both the statements , the overlapping area is a square for sure.Hence we can say that both statements are sufficient.hence C.and the area is '4'.

But we are over looking a few cases.
For example, case 2.

Case 2: Side of square 1 (S1) = half ( side of square 2 (s2)).

S1 = S2/2



l]

As per me this figure follows both the conditions and still gives us a overlapping area which is not square.
So, I think we cant uniquely find an are of theoverlapping region using the bioth statements.

Hence, E.

@jaxis
The question is not to prove that the overlapping area is square or not. It is just to find whether we can determine the area or not. "B" is sufficient. Please check the OA posted above or my first solution (which i have edited since).

Also, In the diagram you have attached , it doesn't seem "C" is in center of the square. I am not sure if that was intentional or not, however based on the facts given in "B" it must be at the center.
As, CE = CF = 2sqrt2
And EF = 4, The triangle ECF is a right angled triangle.

I might have missed something, since i just read few lines of your question, however feel that would change your thought a bit. Let me know if you want us to look at a particular part of it.