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Area of a circular region

Expert replies
by maihuna » Fri Dec 25, 2009 10:21 am
Is the area of a circular region less than the area of a semi circular region?

1. The radius of the circle is less than the radius of the semi circle

2. The circumference of the circle is less than the perimeter of the semi circular region.
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Source: — Data Sufficiency |

by linkinpark » Sat Dec 26, 2009 1:18 am
I would go with E,
stmt 1 and 2 essentially give same info i.e. radius of circle is less than that of semi-circle

now consider r1=4 for full circle and r2=8 for semi-circle
a1=area of circle = 16pi and a2=area of semi-circle = 1/2*pi*8^2 = 32pi, in this case a1<a2 but what if r1=4 and r2=5 in that case 16pi > 1/2*pi*25 i.e. 16pi > 12.5pi
so we can't conclude
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by maihuna » Sat Dec 26, 2009 7:12 am
linkinpark wrote:I would go with E,
stmt 1 and 2 essentially give same info i.e. radius of circle is less than that of semi-circle

now consider r1=4 for full circle and r2=8 for semi-circle
a1=area of circle = 16pi and a2=area of semi-circle = 1/2*pi*8^2 = 32pi, in this case a1<a2 but what if r1=4 and r2=5 in that case 16pi > 1/2*pi*25 i.e. 16pi > 12.5pi
so we can't conclude
Good explanation on part 1, but remember in part 2, one is circumference another is perimeter, for a semicircle perimeter means PI*r+2r if radius of wholecircle is R then given : PI*R^2 = PI*r+2r how can you conclude R>r?
Charged up again to beat the beast :)
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by linkinpark » Sat Dec 26, 2009 7:31 am
maihuna wrote:
linkinpark wrote:I would go with E,
stmt 1 and 2 essentially give same info i.e. radius of circle is less than that of semi-circle

now consider r1=4 for full circle and r2=8 for semi-circle
a1=area of circle = 16pi and a2=area of semi-circle = 1/2*pi*8^2 = 32pi, in this case a1<a2 but what if r1=4 and r2=5 in that case 16pi > 1/2*pi*25 i.e. 16pi > 12.5pi
so we can't conclude
Good explanation on part 1, but remember in part 2, one is circumference another is perimeter, for a semicircle perimeter means PI*r+2r if radius of wholecircle is R then given : PI*R^2 = PI*r+2r how can you conclude R>r?
in stmt2 we're told
pi * R + 2R > 2*pi*r i.e. perimeter > circumference
R*(pi+2) > 2*pi*r isn't that sufficient to indicate R > r because 2*pi is definitely > pi + 2
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by maihuna » Sat Dec 26, 2009 9:10 am
linkinpark wrote:
maihuna wrote:
linkinpark wrote:I would go with E,
stmt 1 and 2 essentially give same info i.e. radius of circle is less than that of semi-circle

now consider r1=4 for full circle and r2=8 for semi-circle
a1=area of circle = 16pi and a2=area of semi-circle = 1/2*pi*8^2 = 32pi, in this case a1<a2 but what if r1=4 and r2=5 in that case 16pi > 1/2*pi*25 i.e. 16pi > 12.5pi
so we can't conclude
Good explanation on part 1, but remember in part 2, one is circumference another is perimeter, for a semicircle perimeter means PI*r+2r if radius of wholecircle is R then given : PI*R^2 = PI*r+2r how can you conclude R>r?
in stmt2 we're told
pi * R + 2R > 2*pi*r i.e. perimeter > circumference
R*(pi+2) > 2*pi*r isn't that sufficient to indicate R > r because 2*pi is definitely > pi + 2
R > r*(2*PI)/(PI+2)
R > 1.1r

humm yeas since R > 1.1 r so R>r, right
Charged up again to beat the beast :)
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