BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

ARC

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 416
Joined: Tue Aug 30, 2011 2:18 pmFollowed by: 9 members
Location: Delhi, India
Thanked: 13 times

by vaibhavgupta » Sat Nov 05, 2011 9:31 am
gmatblood wrote:Please help to answer this question.

IMO B

OA?
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Sat Nov 05, 2011 9:47 am
Length of arc AXB = 2*(Length of arc BZC)
Length of arc AYC = 3*(Length of arc AXB) = 6*(Length of arc BZC)

Hence, circumference of the circle = (Length of arc AXB) + (Length of arc BZC) + (Length of arc AYC) = (1 + 2 + 6)*(Length of arc BZC) = 9*(Length of arc BZC) = (9/2)*(Length of arc AXB)

Now circumference of the circle subtends an angle of 360° in the center of the circle. Say, arc AXB subtends an angle of x° in the center.

Then, (9/2)*(Length of arc AXB) subtends an angle of 360° in the center of the circle.
So, length of arc AXB will subtend an angle of (2/9)*360° = 80° in the center of the circle.

Now, measure of angle BCA = half of the measure of the angle subtended by arc AXB in the center of the circle = 40°

The correct answer is B.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 amFollowed by: 9 members
Location: New Delhi, India
Thanked: 130 times
GMAT Score:720

by rijul007 » Sat Nov 05, 2011 9:57 am
Image
From the figure above :
Angle A = a
Angle B = b
Angle C = c

Circumference of thecircle = m

AXB = x = (2c/360) * m
BZC = z = (2a/360) * m
CYA = y = (2b/360) * m

x = 2z
2c = 2(2a)
c= 2a

y = 3x
2b = 3(2c)
b = 3c

2a + 2b + 2c = 360
a+b+c = 180
c/2 + 3c + c = 180
9c/2 = 180
c = 40

Option B
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 489
Joined: Tue Jul 05, 2011 11:10 amFollowed by: 5 members
Thanked: 28 times

by gmatblood » Sat Nov 05, 2011 10:28 am
Anurag@Gurome wrote:Length of arc AXB = 2*(Length of arc BZC)
Length of arc AYC = 3*(Length of arc AXB) = 6*(Length of arc BZC)

Hence, circumference of the circle = (Length of arc AXB) + (Length of arc BZC) + (Length of arc AYC) = (1 + 2 + 6)*(Length of arc BZC) = 9*(Length of arc BZC) = (9/2)*(Length of arc AXB)

Now circumference of the circle subtends an angle of 360° in the center of the circle. Say, arc AXB subtends an angle of x° in the center.

Then, (9/2)*(Length of arc AXB) subtends an angle of 360° in the center of the circle.
So, length of arc AXB will subtend an angle of (2/9)*360° = 80° in the center of the circle.

Now, measure of angle BCA = half of the measure of the angle subtended by arc AXB in the center of the circle = 40°

The correct answer is B.
Could you please elaborate on the last part of the solution!

Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Sat Nov 05, 2011 10:40 am
There is a theorem which says, the angle at the center of a circle is twice the angle at the circumference if both angles stand on the same arc.

For proof, have a look at the middle of the following webpage with a heading "Angle at the Center" : https://www.mathsrevision.net/gcse/pages.php?page=13

Hence, measure of angle BCA = half of the measure of the angle subtended by arc AXB in the center of the circle as they both stand on the same arc, i.e. AXB
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1