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Arabian Horses - Good One!

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by Matt@VeritasPrep » Wed May 24, 2017 4:34 pm
If the groups ARE distinct, the problem is easier: just (9 choose 3) * (6 choose 3), then you're set.
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GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pmFollowed by: 119 members
Location: East Bay all the way
Thanked: 625 times
GMAT Score:780

by Matt@VeritasPrep » Wed May 24, 2017 4:37 pm
Brent@GMATPrepNow wrote:
puneetkhurana2000 wrote:Note:- This question should be out of scope for GMAT.
I think this is a 700+ level question, but I don't think it's out of scope (IMHO)

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Brent
It's a great example of how difficulty is determined as much by obscurity as by the challenges of the problem itself. If you've done a little combinatorics, the problem is pretty easy, but enough of the GMAT test taking population HASN'T done combinatorics that the problem is assigned a high rank. (The same is true of many standard deviation questions.)
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GMAT Instructor
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GMAT Score:780

by Matt@VeritasPrep » Wed May 24, 2017 4:39 pm
puneetkhurana2000 wrote:Note:- This question should be out of scope for GMAT.
Nah, definitely fair game. The GMAT would use smaller numbers, though, something like 4 horses for 2 carts or 6 horses for 3.
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