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by maihuna » Thu Jun 04, 2009 5:05 am
A sum of money is distributed amongst a certain number of persons, the second receives $1 more than the first, the third$2 more than the second, the fourth $3 more than the third and so on, If the first persons get$1 and the last person $67, what is the number of persons and sum distributed? 12 persons$1190
12 persons $1490 12 persons$1560
14 persons $1350 14 persons$1490
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by sacx » Thu Jun 04, 2009 5:17 am
I am getting 12 people and \$298. Don't know where I am going wrong

first person = 1
2nd = 2, 3rd = 4, 4th = 7 and the sequence continues as 11,16,22,29,37, 46,56,67
SACX

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by tdadic84 » Thu Jun 04, 2009 5:42 am
i also get 12 and 298....

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by agoyal2 » Thu Jun 04, 2009 6:19 am
Me too, the sequence is 1, 2, 4, 5, 11, 16, 22, 29, 37, 46, 56, 67. Adds up to 298.

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