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by shashank.ism » Tue Feb 09, 2010 1:17 pm
If the sum of five consecutive positive integers is A, then the sum of the next five consecutive integers in terms of A is:

A+1
A+5
A+25
2A
5A
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by abhi332 » Tue Feb 09, 2010 3:51 pm
Let A= A1+A2+A3+A4+A5

if we want to add 5 more consecutive numbers then

Sum of the next five consecutive integers = (A1+5)+(A2+5)+(A3+5)+(A4+5)+(A5+5)

Sum = A1+A2+A3+A4+A5 +25

Sum = A +25
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by jeffedwards » Tue Feb 09, 2010 4:45 pm
shashank.ism wrote:If the sum of five consecutive positive integers is A, then the sum of the next five consecutive integers in terms of A is:

A+1
A+5
A+25
2A
5A
When it doubt just plug in numbers:

1+2+3+4+5 = 15 (or A)
5+7+8+9+10 = 40 (or A+25)
40-15=25

A+25 is your answer

Another hint, don't add the numbers to get the total. Just pick the middle number in each set and times that number by five.
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