ratio of Area of similar triangles = ratio of square of similiar sidesawilhelm wrote:Two similar triangles have bases s and S. If the area of the triangle with base S is twice the area of the tiangle with base s, then in terms of s, S =
a) ((sqrt2)s)/2
b) ((sqrt3)s)/2
c) (sqrt2)s
d) (sqrt3)s
e) 2s
therefore
A2 = 2* A1
A1/A2 = s^2/S^2
A1/2A1 = s^2/S^2
1/2 = s^2/S^2
1/sqrt(2) = s/S
S = sqrt(2)s
IMO D
