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Imaginary number and roots

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by MOARQUESTIONS » Wed Nov 02, 2011 3:11 pm
I came across this in the manhattan guide,

(sqrt(x^2 - 2)) - (sqrt(x)) = 0

When you solve it, you get two roots, x = -1 and x = 2

However the answer is only 2 because if you sub in -1 into the equation it will be an imaginary number.

If the GMAT posed this type of question, asking for the roots, would the roots be 2 and -1 or would it be just 2 because they're not really testing your knowledge on imaginary numbers, just the fact that there are imaginary numbers?

Thanks.
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Source: — Problem Solving |

by neelgandham » Wed Nov 02, 2011 4:57 pm
I reckon it is just 2!
Anil Gandham
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by shankar.ashwin » Wed Nov 02, 2011 11:06 pm
Just to add, the GMAT would explicitly mention REAL roots if this question was to be asked. Though complex numbers are out of scope, GMAT would still mention REAL. If not Math purist could protest that technically there are 2 roots and not 1 :) and I guess the GMAC will not let that happen
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