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Any clue to solve the problem

Expert replies
by ksb214 » Sun Jun 21, 2009 7:20 pm
This is the problem from GMAC Test 1. I dont know how to solve it. :x
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Source: — Data Sufficiency |

by tohellandback » Sun Jun 21, 2009 8:49 pm
IMO B
1. NOT SUFFICIENT. we only know the ration. to find the exact number , we need the exact number of children or women

2. since number of men has to be an integer. the number of women must be 25 so that children are 10. and men are 22
The powers of two are bloody impolite!!
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by ghacker » Sun Jun 21, 2009 10:57 pm
The answer is C

We know that men , women and children cannot be fractions the numbers should be integers

We are given the ration of W:C = 5:2

Statement I : C:M = 5:11 , but we only know the ratios not the actual values so insufficient

Statement II : no of women <30 , but where are the men ????
not sufficient

take I and II , we know the following

W:C =5:2 , C:M = 5:11 and W<30 what can we say

We know that W<30 and W:C =5:2 so W can take 5,10,15,20,25 if W can take the above values C can take 2,4,6,8,10 , when W takes these values the only value which satisfies C:M = 5:11 is C= 10

So M = 22
hence we get the answer
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by tohellandback » Sun Jun 21, 2009 11:00 pm
ghacker wrote:The answer is C

We know that men , women and children cannot be fractions the numbers should be integers

We are given the ration of W:C = 5:2

Statement I : C:M = 5:11 , but we only know the ratios not the actual values so insufficient

Statement II : no of women <30 , but where are the men ????
not sufficient

take I and II , we know the following

W:C =5:2 , C:M = 5:11 and W<30 what can we say

We know that W<30 and W:C =5:2 so W can take 5,10,15,20,25 if W can take the above values C can take 2,4,6,8,10 , when W takes these values the only value which satisfies C:M = 5:11 is C= 10

So M = 22
hence we get the answer
don't you think W<30 is enough to conclude that w=25 ?
The powers of two are bloody impolite!!
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by ghacker » Sun Jun 21, 2009 11:12 pm
Hi tohellandback

I dont think that W<30 alone is sufficient

Assume W<30 .We are also give that W:C= 5:2

But we don't know the the number of men , if W :C =5:2 we can have
the following triplets (W,C,M)

{5,2, any figure for M},{10,4, any figure for M}...............{25,10, any figure for M}....................................................... will go on ... why ? because we do not know the total number in the tour party , So M can take , theatrically , any value between zero and infinity

So its insufficient to get an exact value for M
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by tohellandback » Mon Jun 22, 2009 12:14 am
ghacker wrote:Hi tohellandback

I dont think that W<30 alone is sufficient

Assume W<30 .We are also give that W:C= 5:2

But we don't know the the number of men , if W :C =5:2 we can have
the following triplets (W,C,M)

{5,2, any figure for M},{10,4, any figure for M}...............{25,10, any figure for M}....................................................... will go on ... why ? because we do not know the total number in the tour party , So M can take , theatrically , any value between zero and infinity

So its insufficient to get an exact value for M
I don't think so..
the number of men has to be an integer. only with W=25, you can have M= an integer.
so the options (5,2),(10,4) etc are all out

oops.. sorry I was doing the same thing thing as you but written the option wrong...

I am really sorry for taking your time..
The powers of two are bloody impolite!!
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Thank you !

by ksb214 » Mon Jun 22, 2009 6:01 am
All,

Thank you for the reply. I understood the method of solving the problem.

:D
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