This is the problem from GMAC Test 1. I dont know how to solve it. 
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don't you think W<30 is enough to conclude that w=25 ?ghacker wrote:The answer is C
We know that men , women and children cannot be fractions the numbers should be integers
We are given the ration of W:C = 5:2
Statement I : C:M = 5:11 , but we only know the ratios not the actual values so insufficient
Statement II : no of women <30 , but where are the men ????
not sufficient
take I and II , we know the following
W:C =5:2 , C:M = 5:11 and W<30 what can we say
We know that W<30 and W:C =5:2 so W can take 5,10,15,20,25 if W can take the above values C can take 2,4,6,8,10 , when W takes these values the only value which satisfies C:M = 5:11 is C= 10
So M = 22
hence we get the answer
I don't think so..ghacker wrote:Hi tohellandback
I dont think that W<30 alone is sufficient
Assume W<30 .We are also give that W:C= 5:2
But we don't know the the number of men , if W :C =5:2 we can have
the following triplets (W,C,M)
{5,2, any figure for M},{10,4, any figure for M}...............{25,10, any figure for M}....................................................... will go on ... why ? because we do not know the total number in the tour party , So M can take , theatrically , any value between zero and infinity
So its insufficient to get an exact value for M