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Antifreeze Solution

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Antifreeze Solution

by manik11 » Sun Mar 13, 2016 12:48 am
What percent of an antifreeze solution was originally ethylene glycol?

(1) There would be 16 liters of solution if 4 liters of 50% ethylene glycol solution were added.
(2) After 6 hours in the sun 40% of the water has evaporated, leaving 10 liters of a 60% ethylene glycol solution.

OA : B
Source : Bell Curves
Last edited by manik11 on Sun Mar 13, 2016 4:55 am, edited 1 time in total.
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Source: — Data Sufficiency |
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by MartyMurray » Sun Mar 13, 2016 4:50 am
To answer this question you need some way to tell the ratio of ethylene glycol to the total original solution.

Statement 1:

This only gives the volume of the new solution and gives no information related to the ratio of ethylene glycol to total solution in the original solution.

Insufficient.

Statement 2:

This tells us the following.

The new solution is 60% ethylene glycol. Since there are 10 liters of new solution, there must be 6 liters of ethylene glycol in the new solution and 4 liters of water in the solution.

If there are 6 liters of ethylene glycol in the new solution and none has been added or removed, there were 6 liters of ethylene glycol in the original solution as well.

40% of the water has evaporated, leaving 4 liters of water. From this we could calculate the quantity of water in the original solution.

So we know how much ethylene glycol was in the original solution and we could, but we won't, calculate the quantity of water in the original solution.

Therefore, we could calculate the percentage of ethylene glycol in the original solution.

Sufficient.

The correct answer is B.
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