BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

another way to do OG problem?

Expert replies
by fangtray » Sun Apr 29, 2012 11:56 pm
Hello, I am looking for an alternate way to do this problem that is not the same way as explained in the OG guide.

A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at hte rate of y percent pe ryear. If the total interest earned by the $60,000 for that year was $4,080, what is the value of x?

1) x=3/4y
2) the ratio of the amount that earned interest at the rate of x percent per year to hte amount that earned interest at hte rate of y percent per year was 3/2

thanks!
Join the discussion
Source: — Problem Solving |

by mathbyvemuri » Mon Apr 30, 2012 1:36 am
I didn't go through the explantion given by OG, but the following is my approach:

Let the amount that earned interest at the rate of x percent is A
=> the amount that earned interest at the rate of x percent is 60,000-A

The total interest earned = Ax/100 + (60000-A)y/100 = 4080
=> Ax+(60000-A)y = 408000 ---- (I)

Now let us examine the statements:
statement(1): x = 3y/4
This alone is not sufficient because if we substitute this in the equation (I), it eliminates only one unknown and we will end up with an equation with two unknowns.

statement(2): A/(60000-A) = 3/2
This alone is also not sufficient because if we substitute this in the equation (I), it elimintes only one unknown and we will end up with an equation with two unknowns.

But if we use both the statements together we can find the value of as each statement eliminates one unique unknown.

Hence answer is "C"
Join the discussion

by sanju09 » Mon Apr 30, 2012 2:09 am
fangtray wrote:Hello, I am looking for an alternate way to do this problem that is not the same way as explained in the OG guide.

A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at hte rate of y percent pe ryear. If the total interest earned by the $60,000 for that year was $4,080, what is the value of x?

1) x=3/4y
2) the ratio of the amount that earned interest at the rate of x percent per year to hte amount that earned interest at hte rate of y percent per year was 3/2

thanks!
I didn't see the OG's approach, following is how I see to it:


Let's say that $d earned simple annual interest at the rate of x percent per year, and the remaining $(60,000 - d) earned simple annual interest at the rate of y percent per year, such that the total interest earned by the $60,000 for that year =

$[(d x/100) + {(60,000 - d) y/100}] = $4,080 (Given). To find x from the equation

[(d x/100) + {(60,000 - d) y/100}] = 4,080,

we need to know the values of both d and y.

(1) A relation in x and y can reduce the single available equation into two variables, d and x, and x cannot be found uniquely. Insufficient

(2) With d:(60,000 - d) = 3:2, we can find d uniquely, and this can reduce the single available equation into two variables, x and y, and x cannot be found uniquely. Insufficient

Taking (1) and (2) together, we can put the value of d as obtained from (2) into the reduced equation in d and x as obtained from (1) [spoiler]to answer x uniquely. Sufficient

Take C
[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by GMATGuruNY » Mon Apr 30, 2012 4:16 am
fangtray wrote:Hello, I am looking for an alternate way to do this problem that is not the same way as explained in the OG guide.

A total of $60,000 was invested for one year. Part of this amount earned simple annual interest at the rate of x percent per year, and the rest earned simple annual interest at the rate of y percent per year. If the total interest earned by the $60,000 for that year was $4,080, what is the value of x?

1) x=3/4y
2) the ratio of the amount that earned interest at the rate of x percent per year to hte amount that earned interest at hte rate of y percent per year was 3/2

thanks!
Since 4080 is between 5% and 10% of 60,000, it is likely that x and y are between 5 and 10.

Statement 1: x = (3/4)y
It's possible that x=6 and y=8 or that x=6.6 and that y=8.8.
To accommodate the desired combination of percentages, we could simply adjust the amount invested at each percentage so that the total amount of interest earned = 4080.
Since x can be different values, INSUFFICIENT.

Statement 2: The ratio of the amount that earned interest at the rate of x percent per year to the amount that earned interest at the rate of y percent per year was 3/2.

Sum of the parts of the ratio = 3+2 = 5.
Since the actual amount invested = 60,000, and 60,000/5 = 12000, the two parts of the ratio must be multiplied by 12,000:
12,000(3:2) = 36,000:24,000.
Thus, 36,000 earns x% interest and 24,000 earns y% interest.
It's possible that x=6 or that x=6.6.
To accommodate each value for x, we could simply adjust the value of y so that the total amount of interest earned = 4080.
Since x can be different values, INSUFFICIENT.

Statements 1 and 2 combined:
32,000 earns x% interest and 24,000 earns y% interest.
Since x=(3/4)y, for every 4% of interest earned by the $24,000, 3% interest is earned by the $36,000.
If x=3 and y=4:
(.03)(36,000) + (.04)(24,000) = 1080+960 = 2040.
Since 2040 is half the amount of interest needed, the percentages must be doubled to 6% and 8%.
Thus, x=6.
SUFFICIENT.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion