BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Another Triangle question - Kaplan - 700+

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 87
Joined: Sat Feb 28, 2009 7:01 am
Location: India
Thanked: 2 times
by imhimanshu » Sun Sep 11, 2011 6:40 am
IF the sides of the triangle have lengths x,y and z,x+y =30 and y+z = 20, then which of the following could be the perimeter of the triangle.
1- 28
2- 36
3- 42
options are -
a)1 only
b)2 only
c)1 and 2 only
d)1 and 3 only
e)1,2 and 3 only
OA to follow
Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sun Sep 11, 2011 8:03 am
imhimanshu wrote:IF the sides of the triangle have lengths x,y and z,x+y =30 and y+z = 20, then which of the following could be the perimeter of the triangle.
1- 28
2- 36
3- 42
options are -
a)1 only
b)2 only
c)1 and 2 only
d)1 and 3 only
e)1,2 and 3 only
OA to follow
Thanks
I: x+y+z = 28.
Since x+y=30, it is not possible that x+y+z = 28.
Eliminate any answer choice that includes I.
Eliminate A,C,D and E.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 496
Joined: Tue Jun 07, 2011 5:34 amFollowed by: 1 member
Thanked: 38 times

by sl750 » Sun Sep 11, 2011 9:15 am
Both options 2 and 3 are possible. Are those answer choices correct?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sun Sep 11, 2011 11:12 am
sl750 wrote:Both options 2 and 3 are possible. Are those answer choices correct?
Option III is not possible.
IF the sides of the triangle have lengths x,y and z,x+y =30 and y+z = 20, then which of the following could be the perimeter of the triangle.
1- 28
2- 36
3- 42
The third side of a triangle must be less than the sum of the other 2 sides.

III: x+y+z = 42
Since x+y=30, z=12.
Since z=12 and y+z=20, y=8.
Since y=8 and x+y=30, x=22.
Thus, the 3 sides are x=22, y=8, and z=12.
Such a triangle is not possible.
Given that y+z=20, the third side (x) must be less than 20.
Thus, it is not possible that x=22.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1