another geometry

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 73
Joined: Fri Feb 01, 2008 1:28 am
Location: India
Thanked: 1 times
Followed by:1 members

another geometry

by sandeep_chhabra » Thu May 15, 2008 7:07 am
pls help
Attachments
Quantitative2_Q19.JPG

Master | Next Rank: 500 Posts
Posts: 192
Joined: Tue Apr 29, 2008 7:41 am
Thanked: 14 times

by aatech » Thu May 15, 2008 8:36 am
ANS C

Stmt 1 - Length of AC is given and from the questions 2 angles are given so we can calculate

tan 45 = AC/BC - Calculate BC From here

tan 60 = AC/DC - Calculate DC from here

BC-DC = BD... SUFF

Stmt 2 - BA/DA is given

sin 45 = AC/AB ----- (1)

sin 60 = AC/AD ----- (2)

Divide (1) by (2) and AC can be calculated

once AC is known you can calculate BD as stated for stmt 1 SUFF

Senior | Next Rank: 100 Posts
Posts: 73
Joined: Fri Feb 01, 2008 1:28 am
Location: India
Thanked: 1 times
Followed by:1 members

by sandeep_chhabra » Thu May 15, 2008 9:05 am
But answer is A :(

the simulator does not gives any explanation so cant find its logic.

Master | Next Rank: 500 Posts
Posts: 192
Joined: Tue Apr 29, 2008 7:41 am
Thanked: 14 times

by aatech » Thu May 15, 2008 9:54 am
Hmmmm... After reevaluating I realized that I was wrong when I said

Stmt 2 - BA/DA is given

sin 45 = AC/AB ----- (1)

sin 60 = AC/AD ----- (2)

Divide (1) by (2) and AC can be calculated


Actually AC cannot be calculated as this is commin in NUM and DEN... so will cancel each other...

STUPID MISTAKE... Ans is A

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Thu May 15, 2008 10:42 am
Ans is A

A) sufficient you can find BC and DC and hence BD
B) not sufficient because only ratios are provided

BA/DA = sqrt(6)/2
BA = DA x sqrt(6)/2
BC = BA/sqrt(2) = DA x sqrt(3)/2
DC = DA/2

so BC-DC = DA (sqrt(3)/2-1/2)

hence difference will be in terms of DA or BA hence insufficient.