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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## Annie took a trip consisting of three segments... tagged by: BTGmoderatorLU ##### This topic has 1 expert reply and 0 member replies ### Top Member ## Annie took a trip consisting of three segments... Annie took a trip consisting of three segments at three different speeds: she drove a distance of (5D) at a speed of (2v), then a distance of (4D) at a speed of (3v), then a distance of D at a speed of (6v). In terms of D & v, the average speed of Annie's trip was? $$A.\ \frac{11v}{3}$$ $$B.\ \frac{10v}{3}$$ $$C.\ 3v$$ $$D.\ \frac{5v}{2}$$ $$E.\ 2v$$ The OA is D. I'm confused with this PS question. Experts, any suggestion about the solution? Thanks in advance. ### GMAT/MBA Expert Legendary Member Joined 14 Jan 2015 Posted: 2667 messages Followed by: 122 members Upvotes: 1153 GMAT Score: 770 Top Reply LUANDATO wrote: Annie took a trip consisting of three segments at three different speeds: she drove a distance of (5D) at a speed of (2v), then a distance of (4D) at a speed of (3v), then a distance of D at a speed of (6v). In terms of D & v, the average speed of Annie's trip was? $$A.\ \frac{11v}{3}$$ $$B.\ \frac{10v}{3}$$ $$C.\ 3v$$ $$D.\ \frac{5v}{2}$$ $$E.\ 2v$$ The OA is D. I'm confused with this PS question. Experts, any suggestion about the solution? Thanks in advance. Set D = 6 and v = 1 First leg Distance: 5D = 30 First leg speed = 2v = 2 First leg Time: 30/2 = 15 Second leg Distance: 4D = 24 Second leg speed: 3v = 3 Second leg Time: 8 Third leg Distance: 6 Third leg speed: 6v = 6 Third leg Time: 6/6 = 1 Total distance: 30 + 24 + 6 = 60 Total Time: 15 + 8 + 1 = 24 Avg speed = 60/24 = 5/2 Now plug v =1 into your answer choices and see what gives you 5/2. D is the only option that works. _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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