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An elevator has a weight limit of \(630\,\text{kg}\). It is carrying a group of people of whom the heaviest weighs

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by AAPL » Fri Dec 15, 2023 6:51 am

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An elevator has a weight limit of \(630\,\text{kg}\). It is carrying a group of people of whom the heaviest weighs \(101\,\text{kg}\) and the lightest weighs \(53\,\text{kg}\). What is the maximum possible number of people in the group?

A. \(6\)
B. \(9\)
C. \(10\)
D. \(11\)
E. \(12\)

OA C
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Source: — Problem Solving |

To find the maximum possible number of people, we can subtract the weight of the heaviest person from the weight limit of the elevator and then divide by the weight of the lightest person.
(630 kg - 101 kg) / 53 kg ≈ 10.47
So, the maximum possible number of people in the group is 10. Therefore, the answer is C. 10.
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adamarkin wrote:
Thu Dec 21, 2023 7:05 pm

To find the maximum possible number of people, we can subtract the weight of the heaviest person from the weight limit of the elevator and then divide by the weight of the lightest person.
(630 kg - 101 kg) / 53 kg ≈ 10.47
So, the maximum possible number of people in the group is 10. Therefore, the answer is C. 10.
Oh, I didn't expect the calculation to be so simple! I got it!
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