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m is between 0 and 100

by sanju09 » Wed May 02, 2012 4:16 am
The integer m is between 0 and 100 inclusive. When m is divided by 6, the remainder is 5. How many possible values of m are there?
(A) 15
(B) 16
(C) 17
(D) 18
(E) 19



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by neelgandham » Wed May 02, 2012 10:33 am
m is of the form 6x + 5, where x is an integer
for 0<m<100, x can be any number between 0 and 15, both inclusive. So there are 16 such numbers
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by klmehta03 » Wed May 02, 2012 11:48 am
IMO B ,
M can be 5,11,17,23,29,35,41,47,53,59,65,71,77,83,89,95
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by bryan88 » Wed May 02, 2012 5:04 pm
Using A.P. formula
An=a+(n-1)d
a=5,d=6,An=95

n=16
sanju09 wrote:The integer m is between 0 and 100 inclusive. When m is divided by 6, the remainder is 5. How many possible values of m are there?
(A) 15
(B) 16
(C) 17
(D) 18
(E) 19



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by spartacus1412 » Wed May 02, 2012 7:41 pm
n= 16

for 0<m<100 6 has 16 multiples namely 6, 12, 18......90, 96
hence, there will be 16such numbers which will leave remainder of 5 when divided by 6.
like 5, 11, 17....95

Hope it helps!
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