BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

After each throw of a red die, the face that shows is marked

Expert replies
by BTGmoderatorDC » Thu Jul 26, 2018 10:14 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

After each throw of a red die, the face that shows is marked with a blue stripe. What is the probability that after 6 throws all faces of the die will be marked blue?

A. 3/126

B. 5/324

C. 4/216

D. 4/182

E. 5/216
Join the discussion
Source: — Problem Solving |

by Jay@ManhattanReview » Thu Jul 26, 2018 11:31 pm
BTGmoderatorDC wrote:After each throw of a red die, the face that shows is marked with a blue stripe. What is the probability that after 6 throws all faces of the die will be marked blue?

A. 3/126

B. 5/324

C. 4/216

D. 4/182

E. 5/216
1. First throw: Since all the six faces are red, any face would do; so the probability = 6/6 = 1
2. Second throw: Since one face is blue and five are red, and we need any of the five faces, the probability = 5/6
3. Third throw: Since the two faces are blue and four are red, and we need any of the four faces, the probability = 4/6
4. Fourth throw: Since the three faces are blue and three are red, and we need any of the three faces, the probability = 3/6
5. Fifth throw: Since the four faces are blue and two are red, and we need any of the two faces, the probability = 2/6
6. Sixth throw: Since the five faces are blue and only one is red, and we need that one red face, the probability = 1/6

Combined probability = 1*5/6*4/6*3/6*2/6*1/6 = 5/324

The correct answer: B

Hope this helps!

-Jay
_________________
Manhattan Review Test Prep

Locations: Manhattan Review Chennai | Free GMAT Practice Test | GRE Prep Hyderabad | Jayanagar GRE Coaching | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion

by Jeff@TargetTestPrep » Mon Jul 30, 2018 10:48 am
BTGmoderatorDC wrote:After each throw of a red die, the face that shows is marked with a blue stripe. What is the probability that after 6 throws all faces of the die will be marked blue?

A. 3/126

B. 5/324

C. 4/216

D. 4/182

E. 5/216
There is a 1/1 chance of rolling any number on the first roll, after which the side with that number is marked with blue. In the second roll, there is a 5/6 probability that a red side shows up; in the third roll, there is a 4/6 probability that a red side shows up, and so on.

The total probability is:

1 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6

1 x 5/6 x 2/3 x 1/2 x 1/3 x 1/6 = 10/648 = 5/324

Answer: B

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Join the discussion

by swerve » Tue Jul 31, 2018 10:17 am
Total outcomes = 6^6. (Cause any one of the six faces may appear on the top in each throw).

Favorable outcomes = 6*5*4*3*2*1 = 6! = 720 (Cause the top face shouldn't repeat hence there are 6 acceptable outcomes for the first throw and subsequently 5 acceptable as the face earlier obtained shouldn't repeat an so on...)

Probability = 720/ (6^6) = 5/324

Hence, B is the correct answer. Regards!
Join the discussion